0=v-3/v^-9

Solution for 0=v-3/v^-9 equation:

0=v-3/v^-9

We move all terms to the left:

0-(v-3/v^-9)=0


Domain of the equation: v^-9)!=0

v∈R


We add all the numbers together, and all the variables

-(v-3/v^-9)=0

We get rid of parentheses

-v+3/v^+9=0

We multiply all the terms by the denominator


-v*v^+9*v^+3=0

We add all the numbers together, and all the variables

9v-v*v^+3=0

Wy multiply elements

-1v^2+9v+3=0

a = -1; b = 9; c = +3;
Δ = b2-4ac
Δ = 92-4·(-1)·3
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{93}}{2*-1}=\frac{-9-\sqrt{93}}{-2}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{93}}{2*-1}=\frac{-9+\sqrt{93}}{-2}
$